1.

Complete the reaction.(i) H3BO3 + 373k⟶ A + H2O(ii) A + 413k ⟶ B + H2O(iii) B+ Red hot⟶ C + H2O

Answer»

Boric acid when heated at 373 K gives metaboric acid (A) and A heated at 413 K it gives tetraboric acid (B). B heated at red hot it gives boric anhydride (C)

AMetaboric acidHBO2
BTetraboric acidH2B4O7
CBoric anhydrideB2O3


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