1.

Complete the table Volume V Temperature T (In Kelvin scale) \(\frac{V}{T}\)546mL 273 K \(\frac{546}{273}\) = 2600mL300K\(\frac{600}{300}\) = 2640mL320 K\(\frac{640}{320}\) = 2660mL330 K ....

Answer»
 Volume V Temperature T (In Kelvin scale) \(\frac{V}{T}\)
546mL 273 K \(\frac{546}{273}\) = 2
600mL300K\(\frac{600}{300}\) = 2
640mL320 K\(\frac{640}{320}\) = 2
660mL330 K


\(\frac{660}{330}\) = 2



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