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Componds `(A)` and `B` are treated with dilute `HCl` separately. The gases liberated are `Y` and `Z` respectively. `Y` turns acidified `K_2 Cr_2 O_7` paper green while `Z` turns lead acetate paper black. The compounds `A` and `B` are respectively :A. `Na_(2)S " and " Na_(2)SO_(3)`B. `Na_(2)SO_(3) " and " Na_(2)S`C. `NaCl " and" Na_(2)CO_(3)`D. `Na_(2)SO_(3) " and " na_(2)SO_(4)` |
Answer» Correct Answer - B `underset((A))Na_(2)SO_(3)+2HCl (aq) to 2NaCl+H_(2)O+underset((X))SO_(2)` `K_(2)Cr_(2)O_(7)+H_(2)SO_(4) + underset((X))3SO_(2) to underset(("Green"))(Cr_(2)(SO_(4))_(3))+K_(2)SO_(4)+H_(2)O` `underset((B))(Na_(2)S)+HCl(aq) to 2NaCl+underset((Y))(H_(2)S)` `underset((Y))(H_(2)S)+Pb(CH_(3)COO)_(2) to underset(("Black"))(PbS+2CH_(3))COOH` |
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