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Composition fo a colorless liquid is `84.1% C` and `15.9% H` by mass. Its empirical formula isA. `C_(3) H_(7)`B. `C_(4) H_(9)`C. `C_(5) H_(11)`D. `CH_(3)` |
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Answer» Correct Answer - B `n_(C) = (84.1g)/(12.01g mol^(-1)) = 7.00 mol C` `n_(H) = (15.9g)/(1.008g mol^(-1)) = 15.8 mol H` Dividing by the smaller interger 4, we get `n_(C) : n_(H) = (7.00)/(7.00) : (15.8)/(7.00) = 1: 2 26` Mutiplying by the smallest interger 4, we get `(1xx4) : (2.26xx4) = C_(4) H_(9)` |
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