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Compound ` CrO_5` has structure as shown ltbtgt The oxidation number fo Cr in the above compound is .A. `10`B. `5`C. `4`D. `6` |
Answer» Correct Answer - D In the given compound, there are four oxygen atoms in the peroxidge while the fifth oxygen is in the oxide state. If we assume that the oxidation state fo Cr in ` CrO_5` is `x` then ` x+ (-2) + 4 (-4) =0` ltbgt ` x-6 =0` ` x-=+6` Alternatively, we can work out the oxidation number by breaking the bonds heterolytically. Since Cr is forming six bonds whith O atoms, it loses `6` electrons when bonding electrons are given to oxgne. Thus, its oxidation number is `+6`. |
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