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Compound P Liberates H_(2) Gas with Na metal. P gives white precipitate with tollen's reagent, there is no response towards Lucas reagent and compound Q gives instant turbidity with anhydrous ZnCl_(2)/HCl, and with sodium metal 1 mole of compound Q liberates liberates 11.2 litre H_(2) gas at STP. find the structural formula of compound P and Q .

Answer»

P is `CH_(2)=CH-overset(O)overset(||)(C)-H`
Q is `CH_(3)-overset(CH_(3))overset(|)underset(OH)underset(|)(C)-CH_(2)-O-CH_(3)`
P is `CH_(3)-O-=C-H`
Q is `CH_(3)-overset(CH_(3))underset(|)underset(OH)underset(|)(C)-underset(OH)underset(|)(CH)-CH_(3)`

Solution :`CH_(3)-O-C-=C-H` GIVES WHITE precipitate with tollen's REAGENT liberates `H_(2)` gas with Na metal.
`CH_(3)-overset(CH_(3))overset(|)underset(OH)underset(|)(C)-CH_(2)-O-CH_(3)` gives turbidity with anhydrous `ZnCl_(2)//HCl` and liberates half mole `H_(2)` gas with sodium metal


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