1.

Compound X one treatment with HI give Y, Y on treatment with ethanolic KOH gives Z (an isomer of X). Ozonolysis of Z (with H_2O_2 workup) gives a two -carbon carboxylic acid and four carbon ketone . Hence, X is :

Answer»

2-methyl-2-pentene
4-methyl-1-pentene
2,3-dimethyl-2-butene
3-methyl-1-pentene

Answer :D


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