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Comprehension # 2 When two bodies collide normally they exert equal and opposite impulses on each other. Impulse `=` change in linear momentum. Coefficient of restitution between two bodies is given by :- `e = |"Relative velocity of separation"|/|"Relative velocity of approach"| = 1`, for elastic collision Two bodies collide as shown in figure. During collision they exert impulse of magnitude J on each other. If the collision is elastic, the value of J is ............. `N-s` :-A. `10//3`B. `5//4`C. `8//3`D. `3//2`

Answer» Correct Answer - C
By applying conservation of momentum
`2(6) + 1(4) = 1v_(2) + 2v_(1), 16 = v_(2) + 2v_(1)` ….(i)
By applying newton law of collision
`1 = (v_(2) - v_(1))/(2) rArr v_(2) - v_(1) = 2` ……(ii)
`rArr v_(2) = (20)/(3), v_(1) (14)/(3)`
Impulse `=` change in momentum `= (20)/(3) -4 = (8)/(3) N-s`


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