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Comprehension # 9 A 10ml mixture of N_(2), a alkane & O_(2) undergo combustion in Eudiometry tube. There was contraction of 2ml, when residual gases are passed are passed through KOH. To the remaining mixture comprising of only one gas excess H_(2) was added & after combustion the gas product is absorbed by water. causing a reduction in volume of 8ml. Gas produced after introduction of H_(2) in the mixture? Volume of N_(2) present in the mixture?

Answer»

`2ml`
`4ml`
`6ML`
`8ML`

Solution :`NH_(3) = 8 ML`
`{:(N_(2)+3H_(2)rarr2NH_(3)),(4ml""8):}`


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