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Compressibility of water is `5 xx 10^(-10) m^(2) N^(-1)`. The change in volume of 100 mL water subjected to `15 xx 10^(6)` Pa pressure will beA. increases by 0.75 mLB. decreases by 1.50 mLC. increases by 1.50 mLD. decreases by 0.74 mL |
Answer» Correct Answer - d The reciprocal of bulk modulus B is called compressibility Since, `B = ("Change in pressure")/("volume strain")` `implies K = ("Volume strain")/("Change in pressure")` Given, `K = 5 xx 10^(-10) m^(2) N^(-1), Delta P = 15 xx 10^(6) Pa` volume strain `= K xx` change in pressure `:.` volume strain `= 5 xx 10^(-10) xx 15 xx 10^(8)` `implies` volume strain `= 75 xx 10^(-4) mL` `(Delta V)/(V) = 75 xx 10^(-4)` `implies (Delta V)/(100) = 75 xx 10^(-4)` `implies Delta V = 0.7 mL` so. decreases in volume by 0.75 mL |
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