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Compute \(\rm \int {\sin (x+a)\over \sin x}\) dx1. x cos a + sin a ln(|sin x|) + C2. x cos a + ln(|sin x|) + C3. sin a ln(|sin x|) + C4. a[x cos a + sin a ln(|sin x|)] + C |
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Answer» Correct Answer - Option 1 : x cos a + sin a ln(|sin x|) + C Concept: Integral property:
Substitution method: If the function cannot be integrated directly substitution method is used. To integration by substitution is used in the following steps:
Calculation: I = \(\rm ∫ {\sin (x+a)\over \sin x}\) dx ⇒ I = \(\rm ∫ {(\sin x\cos a + \cos x \sin a)\over \sin x} dx\) ⇒ I = \(\rm ∫ {(\sin x\cos a)\over\sin x} + {(\cos x \sin a)\over \sin x} dx\) ⇒ I = ∫ cos a dx + sin a ∫ \(\rm \cos x\over \sin x\) dx Let sin x = t ⇒ cos x dx = dt Substituting sin x as t ⇒ I = x cos a + sin a ∫ \(\rm dt\over t\) + C ⇒ I = x cos a + sin a [ln(|t|)] + C ⇒ I = x cos a + sin a ln(|sin x|) + C
Integration by parts: Integration by parts is a method to find integrals of products. The formula for integrating by parts is given by: ⇒ \(\rm ∫ u vdx=u ∫ vdx- ∫ \left({du\over dx}\times ∫ vdx\right)dx \) + C where u is the function u(x) and v is the function v(x) ILATE rule is Usually, the preference order of this rule is based on some functions such as Inverse, Logarithm, Algebraic, Trigonometric and Exponent. |
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