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Compute the number of ions present in 5.85g of sodium chloride. |
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Answer» Gram formula mass of NaCl=23+35.5=58.5g 58.5g of NaCl have ions=`2xxN_(A)` 5.85g of NaCl have ions=`=(2xxN_(A)xx(5.85g))/((58.5g))` `=(2xx6.022xx10^(23))/(10)=1.2042xx10^(23)"ions"` |
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