Conductivity of 0.12 M Cuso, solution at 298 K is 1.8x 10-2 S cm-1. Ca

1.	Conductivity of 0.12 M Cuso, solution at 298 K is 1.8x 10-2 S cm-1. Calculate its equivalentconductivity
Answer» Conductivity (κ) = 1.8 × 10⁻² S/cm molarity (M) = 0.12M n- factor of CuSO₄ = 2 Normality = n × molarity Normality(N) = 2 × 0.12 = 0.24N Equivalent conductivity (^eq) = κ × 1000/N ⇒equivalent conductivity = 1.8 × 10⁻² × 1000/0.24 = 7500 S.cm²/g/eq

Conductivity of 0.12 M Cuso, solution at 298 K is 1.8x 10-2 S cm-1. Calculate its equivalentconductivity

Answer»

Conductivity (κ) = 1.8 × 10⁻² S/cm molarity (M) = 0.12M n- factor of CuSO₄ = 2 Normality = n × molarity Normality(N) = 2 × 0.12 = 0.24N

Equivalent conductivity (^eq) = κ × 1000/N ⇒equivalent conductivity = 1.8 × 10⁻² × 1000/0.24 = 7500 S.cm²/g/eq