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Conisder an electric field `vecE=E_0hatx` where `E_0` is a constant . The flux through the shaded area (as shown in the figure) due to this field is A. ` 2 E_0a^2`B. ` sqrt 2 E_0 a^2`C. ` E_0 a^2`D. ` (E_0a^2)/(sqrt 2)` |
Answer» Correct Answer - C ` pi = int overline . Overline(dS) =` Ex projected area perpendicualr of e `(x - axis ) = E xx a^2)`. |
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