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Consider a 10 KVA, 2000/200 V, single phase transformer having below following parameters are r1=10Ω, r2=0.1Ω, l1 = 40mH, l2=0.4 mH, M = 10H. Then the expected primary self inductance will be?(a) 100.04H(b) 99.06H(c) 1.0004H(d) 10.04HThis question was addressed to me in class test.This interesting question is from Transformer as a Magnetically Coupled Circuit topic in chapter Transformers of Electrical Machines

Answer»

Correct CHOICE is (a) 100.04H

Easiest EXPLANATION: PRIMARY SELF inductance = L1 = Lm1 + l1

= (N1/N2)*M + l1

= 2000/200*10 + 0.04

=100.04 H.



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