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Consider a 2xx2 matrix A=[a_(ij)] , where A_(ij)=(i+2j)^2/2 Write A |
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Answer» SOLUTION :`a_11-(1+1)^2/2=4/2=2` `a_12=(1+2)^2/2=9/2 ` `a_21=(2+1)^2/2=9/2` `a_22=(2+2)^2/2=16/2=8` HENCE, `A=[[a_11, a_12],[a_21, a_22]]=[[2, 9/2],[9/2, 8]]` |
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