1.

Consider a 2xx2 matrix A=[a_(ij)] , where A_(ij)=(i+2j)^2/2 Write A

Answer»

SOLUTION :`a_11-(1+1)^2/2=4/2=2`
`a_12=(1+2)^2/2=9/2 `
`a_21=(2+1)^2/2=9/2`
`a_22=(2+2)^2/2=16/2=8`
HENCE, `A=[[a_11, a_12],[a_21, a_22]]=[[2, 9/2],[9/2, 8]]`


Discussion

No Comment Found

Related InterviewSolutions