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Consider a binary * operation on the set {1, 2, 3, 4, 5} given by the following multiplication table (Table). (i) Compute (2 * 3) * 4 and 2 * (3 * 4) (ii) * Is commutative? (iii) Compute (2 * 3)*(4 * 5).*12345111111212121311311412141511115 |
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Answer» (i) (2 * 3) * 4 = 1 * 4= 1 2 * (3 * 4) = 2 * 1 = 1 (ii) Since the table is symmetric with main diagonal it is commutative. (iii) (2 * 3) * (4 * 5) = 1 * 1 = 1. |
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