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Consider a body, shown in figure, consisting of two identical balls, each of mass M connected by a light rigid rod. If an impulse J = MV is imparted to the body at one of its ends what would be it angular velocity? A. `V//L`B. `2V//L`C. `V//3L`D. `V//4L` |
Answer» By the conservation of angular momentum about `c.m.` `MV(L)/(2)=[M((L)/(2))^(2)+M((L)/(2))^(2)]omegaimpliesomega=(V)/(L)` |
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