1.

Consider a car moving on a straight road with a speed of `100m//s`. The distance at which car can be stopped is `[mu_k=0.5]`A. `800 m`B. `1000 m`C. `100 m`D. `400 m`

Answer» Correct Answer - B
Retardation due to friction `=mug`
we know `v^(2) =u^(2) + 2as`
`:. 0 = (100)^(2) -2 (mug)s`
or `2mugs =100 xx 100`
or `s = (100xx 100)/(2xx 0.5 xx 10) =1000m` .


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