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Consider a Carnot.s cycle operating between T_(1)=500K and T_(2)=300K producing 1 kJ of mechanical work per cycle. Find the heat transferred to the engine by the reservoirs. |
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Answer» Solution :`(Q_(2))/(Q_(1))=(T_(2))/(T_(1))=(3)/(5), Q_(1)-Q_(2)=W=10^(3)J` `:.Q_(1)(1-(Q_(2))/(Q_(1)))=10^(3)J` `rArr Q_(1)(1-(3)/(5)) =10^(3)J` `:.Q_(1)=(5)/(2)xx10^(3)=2500J` and `Q_(2)="Q"_(1)(3)/(5)=1500J`. |
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