Consider a conducting circular loop placed in a magentic filed as shown. When magnetic field changes with time, magentic flux also changes and emf is induced. `e=-(dphi)/(dt)` If resistance of loop is R then induced current. `i=e/R` For Current, charge must have come into motion. Magnetic force cannot make the statinoary charges to move. Actually there is an induced electric field in the conductor caused by changing magnetic flux, which make the change to move `intvec(E).dvec(l)=e=-(dphi)/(dt)` This induced electric field is non-electrostatic by nature. line integral of `vec(E)` around a closed path is non-zero Refer to above questions, Find the magnitude of line integral of induced electric field along path CD.A. 40 mVB. 60 mVC. 80 mVD. zero

Consider a conducting circular loop placed in a magentic filed as show

1.	Consider a conducting circular loop placed in a magentic filed as shown. When magnetic field changes with time, magentic flux also changes and emf is induced. `e=-(dphi)/(dt)` If resistance of loop is R then induced current. `i=e/R` For Current, charge must have come into motion. Magnetic force cannot make the statinoary charges to move. Actually there is an induced electric field in the conductor caused by changing magnetic flux, which make the change to move `intvec(E).dvec(l)=e=-(dphi)/(dt)` This induced electric field is non-electrostatic by nature. line integral of `vec(E)` around a closed path is non-zero Refer to above questions, Find the magnitude of line integral of induced electric field along path CD.A. 40 mVB. 60 mVC. 80 mVD. zero
Answer» Explanation : Perpendicular distance between CD and O is 20 cm . There fore, induced emf in CD `=d/2I(dB)/(dt)=20/2xx10^(-2)xx20xx10^(-2)xx2` `=40 mV`

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