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Consider a conducting circular loop placed in a magentic filed as shown. When magnetic field changes with time, magentic flux also changes and emf is induced. `e=-(dphi)/(dt)` If resistance of loop is R then induced current. `i=e/R` For Current, charge must have come into motion. Magnetic force cannot make the statinoary charges to move. Actually there is an induced electric field in the conductor caused by changing magnetic flux, which make the change to move `intvec(E).dvec(l)=e=-(dphi)/(dt)` This induced electric field is non-electrostatic by nature. line integral of `vec(E)` around a closed path is non-zero A square non- conducting loop 20 cm on a side is placed in a magnetic field The centre of side AB coincides with the centre of magnetic field The magnetic field is increasing at the rate of 2T/s. Find the magnitude of line integral of induced electric field along path BC. A. 10 mVB. 20 mVC. 30 mVD. zero

Answer» Explanation:
Perpendicular distance between BC and centre O is 10 cm. component of induced electric field along
the rod =`d/2 (dB)/(dt)`
where d =Perpendicular distance from centre to the rod.
Hence, potential difference between the ends of rod
`v=EI=I. d/2 (dB)/(dt)`
`=10/2xx10^(-2)xx20xx10^(-2)xx2=20 mV`
Hence, choice (b) is correct and choices (a),(c) and (d) are wrong.


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