Consider a cycle tyre bering filled with air by a pump. Let V be the volume of the tyre (fixed) and at each stroke of the pump DeltaV(=V) of air is transferred to the tube adiabatically. What is the work done when the pressure in the tube is increased from P_(1)" to "P_(2) ?

Consider a cycle tyre bering filled with air by a pump. Let V be the v

1.	Consider a cycle tyre bering filled with air by a pump. Let V be the volume of the tyre (fixed) and at each stroke of the pump DeltaV(=V) of air is transferred to the tube adiabatically. What is the work done when the pressure in the tube is increased from P_(1)" to "P_(2) ?
Answer» Solution :`P(V+Deltaupsilon)^(GAMMA)=(P+DELTAP)V^(gamma)` `P[1+gamma(Deltaupsilon)/V]=P[1+(Deltap)/P]` `gamma(Deltaupsilon)/V=(Deltap)/P,(dupsilon)/(DP)=V/(gammaP)` W.D =`int_(P_(1))^(P_(2))Pdupsilon= int_(P_(1))^(P_(2))PV/(gammaP)dp=((P_(2)-P_(1)))/gammaV`