Consider a hypothesis H-like atom, the wavelength in Amstrong for the spectral lines for the transition from n=p to n=1 is given as wavelength =1500p^2/p^2 -1 where p>1find the minimum and maximum wavelength

Consider a hypothesis H-like atom, the wavelength in Amstrong for the

1.	Consider a hypothesis H-like atom, the wavelength in Amstrong for the spectral lines for the transition from n=p to n=1 is given as wavelength =1500p^2/p^2 -1 where p>1find the minimum and maximum wavelength
Answer» λ= P 2 −11500p 2 = 1− p 2 1 1500 A ⋅ λ max at p=2 is 2000A ⋅ λ min at p=∞ is 1500A ⋅ E 4 = 150012400 (1− p 2 1 )= 15124 × 1615 E 3 = 15124 (1− 91 ) = 15124 × 98 E 2 = 15124 (1− 41 ) = 15124 × 43 =6.2 eVNow,E 4 −E 3 = 15124 ×( 1615 − 98 )= 15124 × 1447 = 144×15868 =0.40 eVand, E ∞ =IONISATION EnergyIonisation ENERGY=−E ∞ =− 15124 =−8.27 eVIonisation Potential= −eIonisation energy Ionisation Potential=8.27 V