Consider a one -dimensional motion of a particle with total energy E. There are four regions A,B,C and D in which the relation between potential energy E. There are four regions A,B,C and D in which the relation between potential energy V, kinetic energy (K) and total energy E is as given below Region A : V gtERegion B: V lt E Region C :K gt E Region D : V gt E . State with reasons in each

Consider a one -dimensional motion of a particle with total energy E.

1.	Consider a one -dimensional motion of a particle with total energy E. There are four regions A,B,C and D in which the relation between potential energy E. There are four regions A,B,C and D in which the relation between potential energy V, kinetic energy (K) and total energy E is as given below Region A : V gtERegion B: V lt E Region C :K gt E Region D : V gt E . State with reasons in each
Answer» SOLUTION :We know that Total energy `E = PE +KE` `E = V+K ""…..(i)` For region A : Given `V gt E` From Eq. (i) `K = E -V` as ` V gt E RARR E -V lt 0 ` HENCE , `K lt 0 ` , this is not possible . For region B : `V lt E rArr E - V gt 0 ` This is possible because total energy can be GREATER than PE(V) . or region C : Given , `K gt E rArr K - E K - ZE lt 0 ` Which is possible , because PE can be negative . For region D :Given `V gt K ` This is possible because for a system pE (V) MAY be greater than kE (K) .