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Consider a parabola `y=Ax^(2)+B, -x_(0) le x le x_(0)`. If this curve is rotated about y axis, we get a paraboloid surface. The volume below this surface & above x–z plane is given by `V=(piAx_(0)^(4))/2+piBx_(0)^(2)=("volume of cylinder ABCD")/2+"Volume of cylinder CDEF"` Use the above result to answer following question. If the cylinder of previous problem was completely filled, then the minimum angular velocity at which base may be visible is.A. `sqrt((gh)/(a^(2)))`B. `sqrt((2gh)/(a^(2)))`C. `sqrt((gh)/(2a^(2)))`D. `sqrt(4/3(gh)/(a^(2)))` |
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Answer» `y=(omega^(2)x^(2))/(2g)` `h=(omega^(2)a^(2))/(2g)` `omega=sqrt((2gh)/(a^(2)))` |
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