Consider a parabola y2=4x and F be its focus. Let A1(x1,y1),A2(x2,y2),A3(x3,y3),...,An(xn,yn) be n points on the parabola such that xk,yk>0 and ∠OFAk=kπ2n. If limn→∞1nn∑k=1FAk=Pπ, then the value of P is

Consider a parabola y2=4x and F be its focus. Let A1(x1,y1),A2(x2,y2),

1.	Consider a parabola y2=4x and F be its focus. Let A1(x1,y1),A2(x2,y2),A3(x3,y3),...,An(xn,yn) be n points on the parabola such that xk,yk>0 and ∠OFAk=kπ2n. If limn→∞1nn∑k=1FAk=Pπ, then the value of P is
Answer» Consider a parabola $y^{2} = 4 x$ and $F$ be its focus. Let $A_{1} (x_{1}, y_{1}), A_{2} (x_{2}, y_{2}), A_{3} (x_{3}, y_{3}), . . ., A_{n} (x_{n}, y_{n})$ be $n$ points on the parabola such that $x_{k}, y_{k} > 0$ and $∠ O F A_{k} = \frac{k π}{2 n}$ . If $lim n \to \infty \frac{1}{n} n \sum k = 1 F A_{k} = \frac{P}{π}$ , then the value of $P$ is