1.

Consider a polynominal p(x)=x6+2x2+1. If x1,x2,…,x6 are the roots of p(x)=0 and q(x)=x3−1, then the value of 6∏i−1q(xi) is (where ∏ stands for product of terms)

Answer»

Consider a polynominal p(x)=x6+2x2+1. If x1,x2,,x6 are the roots of p(x)=0 and q(x)=x31, then the value of 6i1q(xi) is
(where stands for product of terms)



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