Consider a polynominal p(x)=x6+2x2+1. If x1,x2,…,x6 are the roots of – InterviewSolution

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1.	Consider a polynominal p(x)=x6+2x2+1. If x1,x2,…,x6 are the roots of p(x)=0 and q(x)=x3−1, then the value of 6∏i=1q(xi) is(where ∏ stands for product of terms)
Answer» Consider a polynominal $p (x) = x^{6} + 2 x^{2} + 1$ . If $x_{1}, x_{2}, \dots, x_{6}$ are the roots of $p (x) = 0$ and $q (x) = x^{3} - 1$ , then the value of $6 \prod i = 1 q (x_{i})$ is (where $\prod$ stands for product of terms)

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