Consider a rod of steel having radius of 8 mm and the length of 2 m. If a force of 150 kN stretches it along its lengths , then calculated the stress, percentage strain in the rod if the elongation in length is 7.46 mm.

Consider a rod of steel having radius of 8 mm and the length of 2 m. I

1.	Consider a rod of steel having radius of 8 mm and the length of 2 m. If a force of 150 kN stretches it along its lengths , then calculated the stress, percentage strain in the rod if the elongation in length is 7.46 mm.
Answer» Radius of rod,` r=8 mm=8xx10^(-3)`m,length, L=2 m Applied force, F=150 kN=`15xx10^(4)N` Cross-section area of wire, `A=pir^(2)=pixx(8xx10^(-3))^(2)=201xx10^(-6)m^(2)` `DeltaL=7.46 mm=7.46xx10^(-3)m`, Percentage strain = ? Stress in rod `=(F)/(A)=(15xx10^(4))/(201xx10^(-6))` `=0.0746 xx 10^(10)Nm^(-2)` `=7.46xx10^(8)Nm^(-3)` Longitude strain `=(DeltaL)/(L)=(7.46xx10^(-3))/(2)=3.73xx10^(-3)` Percentage strain `=3.73xx10^(-3)xx100=0.37 %`

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Consider a rod of steel having radius of 8 mm and the length of 2 m. If a force of 150 kN stretches it along its lengths , then calculated the stress, percentage strain in the rod if the elongation in length is 7.46 mm.

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