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Consider a transmission line of characteristic impedance 50 ohms. Let it be terminated at one end by (+ j50) ohm. The VSWR produced by it in the transmission line will be (a) + 1 (b) 0 (c) ∞ (d)+ j |
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Answer» Correct option (c) ∞ Explanation: Reflection coefficient = = (zL - z0)/(zL + z0) = (j50 - 50)/(j50 + 50) = (-50 + j50)/(50 + j50) = √(502 + 502)/√(502 + 502) = 1 VSWR = (1 + ||)/(1 - ||) = (1 + 1)/(1 - 1) = 2/0 = ∞ |
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