Consider a two particle system with particles having masses m_(1)andm_(2). If the first particle is pushed towards the centre of mass through a distance d, by what distance should the second particle be moved, so as to keep the centre of mass at the same position?

Consider a two particle system with particles having masses m_(1)andm_

1.	Consider a two particle system with particles having masses m_(1)andm_(2). If the first particle is pushed towards the centre of mass through a distance d, by what distance should the second particle be moved, so as to keep the centre of mass at the same position?
Answer» d `(m_(2))/(m_(1))d` `(m_(1))/(m_(1)+m_(2))d` `(m_(1))/(m_(2))d` Solution :Suppose a PARTICLE of mass `m_(2)` MOVED a distance x toward CENTRE of mass is x. `therefore (m_(1)d+m_(2)(-x))/(m_(1)+m_(2))=r_(cm)` `therefore m_(1)d-m_(2)x=0 [because r_(cm)=0]` `therefore m_(1)d=m_(2)x` `therefore x=(m_(1))/(m_(2))d`