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Consider a uniform electric field \(\vec E\) = 3× 103\(\hat i\) N/C. What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the YZ plane? |
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Answer» Here, \(\vec E\) = 3 × 103 \(\hat i\) N/C (i.e field is along + direction of x-axis). Surface are, s = (10cm)2 = 10-2m2 When plane is parallel to yz plane, θ = 0° ∴ ϕE (electric flux) = Es cosθ = 3× 103 × 10−2 × cos 0° = 30 Nm2/C. |
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