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Consider an `1100` particels gas system with speeds distribution as follows : 1000 particles each with speed `100 m//s` 2000 particles each wityh speed `200 m//s` 4000 particles each with speed `300 m//s` 3000 particles each with speed `400 m//s` and 1000 particles each with speed `500 m//s` Find the average speed, and rms speed. |
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Answer» Correct Answer - A::B::C The average speed is `v_(av) = ((1000) (100) + (2000) (200) + (4000) (300) +(3000) (400) + (1000) (500))/(1100)` `309 m//s` The rms speed is `v_(rms) = sqrt ((1000)(100)^2 + (2000) (200)^2 + (4000) (300)^2 + (3000) (400)^2 + (1000) (500)^2)/(1100)))` `328 m//s`. |
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