1.

Consider an arithmetic sequence whose 7th term is 34 and 15th term is 66.a. Find the common difference,b. Find the 20th term.

Answer»

a. 15th term can be obtained by adding 7th term ‘ and 8 times the common difference.

x15 = x7 + 8d 

66 = 34 + 8d

8d = 66 – 34 = 32

d = \(\frac{32}{8}\) = 4 

d. 20th term can be obtained by adding 15th term and 5 times the common difference.

x20 = x15 + 8d

= 66 + 5 × 4 = 86



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