1.

Consider an equation with x as a variable 7sin3x−2sin9x=sec2θ+4 cosec2θ. Then the value of 15π((minimum positive root)−(maximum negative root)) is

Answer» Consider an equation with x as a variable 7sin3x2sin9x=sec2θ+4 cosec2θ. Then the value of 15π((minimum positive root)(maximum negative root)) is


Discussion

No Comment Found