Consider an ionic solid that dissolves in water according to the equation: M_(n)X_(m(s)) nM_(aq)^(m+)n + mX_(aq)^(n-) . The equilibrium constant for this reaction, K _(sp)=[M^(m+)]^(n) [X^(n-)]^(m)is known as the solubility product of M_(n), X_(m). The form of this euquilibrium is important in understanding effects such as the influence of pH, complex fomation and common ion cffect. Equilibrium constant in solution should be written correctly using activities and not concentrations. The difference between thesc quantities is large in concentrated ionic solutions and K_(sp) is quantitatively reliable as a guide of solubilities only for very dilute solutions, If solubility product of AB type salt is 4xx 10^(-10) at 18^(@)C, and M.W of AB is 143.5 g/mol. If ppt. of AB is washed with 5 lit water, loss in wt. of ppt. of AB is

Consider an ionic solid that dissolves in water according to the equat

1.	Consider an ionic solid that dissolves in water according to the equation: M_(n)X_(m(s)) nM_(aq)^(m+)n + mX_(aq)^(n-) . The equilibrium constant for this reaction, K _(sp)=[M^(m+)]^(n) [X^(n-)]^(m)is known as the solubility product of M_(n), X_(m). The form of this euquilibrium is important in understanding effects such as the influence of pH, complex fomation and common ion cffect. Equilibrium constant in solution should be written correctly using activities and not concentrations. The difference between thesc quantities is large in concentrated ionic solutions and K_(sp) is quantitatively reliable as a guide of solubilities only for very dilute solutions, If solubility product of AB type salt is 4xx 10^(-10) at 18^(@)C, and M.W of AB is 143.5 g/mol. If ppt. of AB is washed with 5 lit water, loss in wt. of ppt. of AB is
Answer» `10^(-4)mol// "lit"` ` 10 ^(-4) ` gm ` 10 ^(-4) mol ` ` 10 ^(-4) MG ` SOLUTION :Solubility ` = 2. 87xx 10 ^(-3) gm ` Moles dissolved = ` ( 287 xx 10 ^(-5))/( 143. 5) ` ` "" = 2xx 10 ^(-5)` moles = per lit ` 2xx 10 ^(-5)` moles - 1 lit `x ""5" lit " ` ` x= 10 ^(-4)" moles " `