Consider an `n-p-n` transistor amplifer in common-emitter configuration. The current gain of the transistor is `100`. If the collector current changes by `1mA`, what will be the change in emitter current?A. `1.01 mA`B. `1.1 mA`C. `0.01 mA`D. `10 mA`

Consider an `n-p-n` transistor amplifer in common-emitter configuratio

1.	Consider an `n-p-n` transistor amplifer in common-emitter configuration. The current gain of the transistor is `100`. If the collector current changes by `1mA`, what will be the change in emitter current?A. `1.01 mA`B. `1.1 mA`C. `0.01 mA`D. `10 mA`
Answer» Correct Answer - A Current gain `=(chang e i n coll ect or current)/(chang e i n base current)` `beta=(Deltai_(C))/(Deltai_(B))` Also `i_(E)=i_(B)+i_(C) implies Deltai_(E)=Deltai_(B)+Deltai_(C)` `beta=(Deltai_(C))/(Deltai_(E)-Deltai_(C))` Given, `beta=100,Deltai_(C)=1mA` `:. 100=1/(Deltai_(E)-1), Deltai_(E)-1=1/100=0.01` `Deltai_(E)=1+0.01=1.01 mA`

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Consider an `n-p-n` transistor amplifer in common-emitter configuration. The current gain of the transistor is `100`. If the collector current changes by `1mA`, what will be the change in emitter current?A. `1.01 mA`B. `1.1 mA`C. `0.01 mA`D. `10 mA`

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