1.

Consider any set of observations x_(1),x_(2),x_(3),..,x_(101). It is given that x_(1) lt x_(2) lt x_(3) lt .. Lt x_(100) lt x_(101), then the mean deviation of this set of observations about a point k is minimum when k equals

Answer»

`x_(1)`
`x_(51)`
`(x_(1)+x_(2)+..+x_(101))/(101)`
`x_(50)`

Solution :Mean deviation is MINIMUM when it is CONSIDERED about an item equidistant from the BEGINNING and the END, i.e., the median. In this case, the median is `(101+1)/(2)` th, i.e., 51st item, i.e., `x_(51)`.


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