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Consider Example 22. Takin the coefficient of friction, mu to be 0.5, calculate the maximum compression of the spring. |
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Answer» Solution :In the PRESENCE of friction, boththe SPRING force and the frictional force f act so as to oppose the COMPRESSION of the spring. WORK done by the two forces `W=-(1)/(2)kx_(m)^(2)-f(x_(m))` `W=-(1)/(2)kx_(m)^(2)-mumg(x_(m))` `( :' f=muR=mumg)` and change in K.E. `DeltaK=K_(f)-K_(i)=0-(1)/(2)mv^(2)` Applying work energy theorem, `DeltaK=W` `:. -(1)/(2)mv^(2)=-(1)/(2)kx_(m)^(2)-mumg(x_m)` `:.kx_(m)^(2)+2mumg(x_(m))-mv^(2)=0` It is a quadratic equation in `x_(m)` `:. x_(m)=(-2mumg+[4mu^(2)m^(2)g^(2)+4mkv^(2)]^(1//2))/(2K)` Putting the numerical values and solving, we get `_(m)=1.35m` |
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