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Consider Example 22. Takin the coefficient of friction, mu to be 0.5, calculate the maximum compression of the spring.

Answer»

Solution :In the PRESENCE of friction, boththe SPRING force and the frictional force f act so as to oppose the COMPRESSION of the spring.
WORK done by the two forces
`W=-(1)/(2)kx_(m)^(2)-f(x_(m))`
`W=-(1)/(2)kx_(m)^(2)-mumg(x_(m))`
`( :' f=muR=mumg)`
and change in K.E.
`DeltaK=K_(f)-K_(i)=0-(1)/(2)mv^(2)`
Applying work energy theorem, `DeltaK=W`
`:. -(1)/(2)mv^(2)=-(1)/(2)kx_(m)^(2)-mumg(x_m)`
`:.kx_(m)^(2)+2mumg(x_(m))-mv^(2)=0`
It is a quadratic equation in `x_(m)`
`:. x_(m)=(-2mumg+[4mu^(2)m^(2)g^(2)+4mkv^(2)]^(1//2))/(2K)`
Putting the numerical values and solving, we get `_(m)=1.35m`


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