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Consider f : [3, ∞) → [1, ∞) given by f(x) = x2 – 6x + 10. Find f-1 |
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Answer» f(x) = (x – 3)2 + 1 y = (x – 3)2 + 1 ⇒ (x – 3)2 = y – 1 ⇒ x = \(\sqrt{y-1} + 3\) ∴ f-1(x) = \(\sqrt{x-1} + 3\) |
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