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Consider, f(x)=(x+2a)(x+a-4)(a in R), g(x)=k(x^(2)+x)+3k+x(k in R) and h(x)=(1-sin theta)x^(2)+2(1-sin theta)x-3 sin theta ( theta in R-(4n+1)(pi)/(2), n in I) If f(x) lt 0 for -1 le x le 1, then 'a' satisfies |
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Answer» `1/2 LT a LT3` |
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