Saved Bookmarks
| 1. |
Consider folllowing reaction at 300 K : N_(2)O_(5)(g)hArrN_(2)O_(5)(g)+O_(2)(g)K_(c)=5 N_(2)O_(5)(g)hArrN_(2)O(g)+O_(2)(g). For second reaction, if energy of activation of forward and backward reaction are respectively 85 and 42KJ//"mole", then at 400K, K_(c) for the second reaction is : |
|
Answer» 10 |
|