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Consider P,Q,R to be vertices with integral coordinates and (|PR|+|RQ|)^(2)lt8. Area (/_\PQR)+1 then |
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Answer» `/_R` can be a right angle `|PR|.|RQ|ge 2Ar(/_\PQR)` `implies8Ar(/_\PQR)le|PR|^(2)+|RQ|^(2)+4aR(/_\PQR)` `le|PR|^(2)+|RQ|^(2)+2.|PR|^(2).|RQ|lt8Ar(/_\PQR)+1` `implies8Ar(/_\PQR)=|PQ|^(2)+|QR|^(2)+4Ar(/_\PQR)` and `|PQ|^(2)+|QR|^(2)=2|PQ|.|QR|=4Ar(/_\PQR)` `:./_R=9^(@)` and `RP=RQ`
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