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Consider parallel conducting rails separated by a distance l. There exists a uniform magnetic field B perpendicular to the plane of the rails as shown in Fig. Two conducting wires each of length l are placed so as to slide on parallel conducting rails. One of the wires is given a velocity `v_(0)` parallel to the rails. Till steady state is achieved, loss in kinetic energy of the system is A. zeroB. `3.4 mv_(0)^(2)`C. `1/4 mv_(0)^(2)`D. `3/8mv_(0)^(2)` |
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Answer» Correct Answer - C In steady state, velocity of both wires will becomes same. `2 mv=mv_(0) implies v=v_(0)//2` Loss in `KE=1/2 mv_(0)^(2)-2 [1/2 mv^(2)]=1/4 mv_(0)^(2)`. |
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