Saved Bookmarks
| 1. |
Consider the amplitude modulated (AM) signal AC cos\(\omega\)ct+2 cos\(\omega\)m t cos\(\omega\)ct For demodulating the signal using envelope detector, the minimum value of AC should be (a) 2 (b) 1 (c) 0.5(d) 0 |
|
Answer» (a) 2 Modulated signal is given as \(\theta\)A(t) = [Ac+ 2os\(\omega\)mt] cos\(\omega\)ct Note that for envelope detection the modulation should not go beyond full modulation i.e. \(\mu\) = 1, so amplitude of baseband signal has to be less than the carrier amplitude (Ac) |f(t)|max ≤ Ac |2 osmt|max= 2 ≤ Ac Or Ac >= 2 |
|