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Consider the arrangement of bulbs shown in the drawing. Each of three bulbs contains a gas at pressure shown. What is pressure of system when all stopcocks are opened. Assuming that temperature remain constant. (Neglect the volume of capollary tubing connecting bulbs) A. 440 torrB. 200 torrC. 360 torrD. 320 torr |
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Answer» Correct Answer - A After all stopcocks are opened, gases move unit partial pressure becomes same in all bulbs For `O_(2)` gas `P_(1) V_(1) = P_(2) V_(2)` `P_(1) = 300` torr, `P_(2)` ? `V_(1) = 1` litre, `V_(2) = 2.5` litre `300 xx 1 = P_(2) xx 2.5` `P_(2) = 120` torr For He gas `P_(1) V_(1) = P_(2)V_(2)` `P_(1) = 600` torr, `P_(2) =` ? `V_(1) = 1` litre, `V_(2) = 2.5` litre `600 xx 1 = P_(2) xx 2.5` `P_(2) = 240` torr For `N_(2)` gas `P_(1)V_(1) = P_(2)V_(2)` `P_(1) = 400` torr, `P_(2) =` ? `V_(1) = 0.5` litre, `V_(2) = 2.5` litre `400 xx (1)/(2) = P_(2) xx (5)/(2)` `P_(2) = 80` torr Pressure of system `= P_(O_(2)) + P_(N_(2)) + P_(He)` `= 120 + 80 + 240` `= 440` torr |
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