1.

Consider the binary operation * and 0 defined by the following tables on set S = {a, b, c, d}.

Answer»

We observe the following: 

a * b = b * a = b 

c * a = a * c = c 

a * d = d * a = d 

b * c = c * b = d 

b * d = d * b = c 

c * d = d * c = b 

There ‘ * ’ is commutative. 

Also, 

a * (b * c) = a * (d) = d (From above) 

(a * b) * c = (b) * c = d (Also from above) 

Hence, ‘ * ’ is associative too. 

Therefore, to find the identity element, e for e belong to S, we need: 

a * e = e * a = a, a belong to S. 

Therefore, a * e = a 

e = a (since, a * a = a, from the given table) 

To find out the inverse, a * x = e = b * x, x belongs to S 

a * x = e 

x = a (From the given table) 

Therefore, the inverse of a is a, b is b, c is c and d is d.



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