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Consider the binary operation * and 0 defined by the following tables on set S = {a, b, c, d}. |
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Answer» We observe the following: a * b = b * a = b c * a = a * c = c a * d = d * a = d b * c = c * b = d b * d = d * b = c c * d = d * c = b There ‘ * ’ is commutative. Also, a * (b * c) = a * (d) = d (From above) (a * b) * c = (b) * c = d (Also from above) Hence, ‘ * ’ is associative too. Therefore, to find the identity element, e for e belong to S, we need: a * e = e * a = a, a belong to S. Therefore, a * e = a e = a (since, a * a = a, from the given table) To find out the inverse, a * x = e = b * x, x belongs to S a * x = e x = a (From the given table) Therefore, the inverse of a is a, b is b, c is c and d is d. |
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