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Consider the cell reaction `:` `Mg(s)+Cu^(2+)(aq) rarr Cu(s) +Mg^(2+)(aq)` If `E^(c-)._(Mg^(2+)|Mg(s))` and `E^(c-)._(Cu^(2+)|Cu(s))` are `-2.37` and `0.34V`, respectively. `E^(c-)._(cell)` isA. 2.03 VB. `-2.03 V`C. `+ 2.71 V`D. `-2.71 V` |
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Answer» Correct Answer - C `E_(cell)^(@)=E_("Cathode")^(@)-E_("Anode")^(@)` `=E_("Reduced species")^(@)-E_("Oxidised species")^(@)` `=0.34-(-2.37)=+2.71 V` |
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