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Consider the circle x^(2)+y^(2)=1 and thhe parabola y=ax^(2)b(agt0). This circle and parabola intersect at |
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Answer» FOUR distinct POINTS is `agtbgt1` `impliesa^(2)x^(4)+(1-2ab)x^(2)+(b^(2)-1)=0` `impliesa^(2)t^(2)+(1-2ab)t+(b^(2)-1)=0` `impliesf(t)=0` `D=4a^(2)-4ab+1` `agtbgt1impliesDgt0`, `f(0)gt0` and `(2ab-1)/(2a^(2))gt0impliest_(1)gt0,t_(2)gt0` `implies` four distinct real values of x `blt-1impliesDgt0,f(0)gt0` and `(2ab-1)/(2a^(2))lt0` `impliest_(1)lt0,t_(2)lt0implies` no real value of x `-1ltblt1impliesf(0)lt0impliest_(1)gt0,t_(2)lt0` `implies` two distinct real values of x |
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